Explanation:
α = ẞ / (1 + ẞ)
Correct Answered:
Wrong Answered:
1. In a BJT transistor a is common base current gain and ẞ is common emitter current gain. What is relation between α and ẞ
A
α = ẞ/(1 - ẞ)
B
α = ẞ/(1 +ẞ)
C
α = ẞ/(ẞ - 1)
D
Relation between α and ẞ depends on circuit
α = ẞ / (1 + ẞ)
Correct Answered:
Wrong Answered:
2. Match the following Operation Characteristics: Column - A (Diodes) Column - B (Characteristics) i) Zener Diode 1. Negative resistance region due to tunneling
ii) Tunnel Diode 2. Sharp breakdown voltage in reverse bias
iii) Schottky Diode 3. Low forward voltage drop (~0.2-0.3 V)
iv) Varactor Diode 4. Junction capacitance varies with reverse bias
Choose the correct option:
A
i-2, ii-1, iii-3, iv-4
B
i-2, ii-4, iii-1, iv-3
C
i-2, ii-4, iii-1, iv-3
D
i-4, ii-3, iii-2, iv-1
i-2, ii-1, iii-3, iv-4
Correct Answered:
Wrong Answered:
A
1-4,2-3,3-2,4-1
B
1-3,2-4,3-2,4-1
C
1-2,2-3,3-4,4-1
D
1-4,2-2,3-1,4-3
Mapping: VHF=TV/FM, UHF=cellular, HF=shortwave, SHF=satellite.
Correct Answered:
Wrong Answered:
A
Includes audio, video, sync
B
Contains only video component
C
Uses one sideband only
D
Used only in SHF
Composite video signal includes video, audio and sync signals.
Correct Answered:
Wrong Answered:
A
1-1,2-2,3-3,4-4
B
1-2,2-1,3-3,4-4
C
1-3,2-1,3-4,4-2
D
1-4,2-3,3-2,4-1
Correct mapping: Progressive=scan sequence, SSB=one sideband, UHF=300MHz-3GHz, Negative pulses=darker area.
Correct Answered:
Wrong Answered:
A
Top to bottom one pass
B
Odd lines then even lines
C
All lines at once
D
Half lines in passes
Interlaced scanning scans odd then even lines.
Correct Answered:
Wrong Answered:
A
Phase
B
Frequency
C
Both
D
None
SSB-SC can be generated by both phase and filter methods.
Correct Answered:
Wrong Answered:
8. Match Medium type with Frequency: 1.Open wire i.100kHz 2.Twisted pair ii.100MHz 3.Coaxial cable. iii.5kHz.
A
1-3,2-1,3-2
B
1-2,2-3,3-1
C
1-1,2-3,3-2
D
1-2,2-1,3-3
Open wire=5kHz, Twisted pair=100kHz, Coaxial=100MHz.
Correct Answered:
Wrong Answered:
A
Uniform current distribution
B
Effective length=3?physical length
C
Radiation max ? to axis
D
Impedance independent
Radiation max normal to dipole axis.
Correct Answered:
Wrong Answered:
A
Single-channel 1D
B
3-channel 3D
C
3-channel 1D
D
Single-channel 3D
Colour TV uses 3 colour channels, one dimensional.
Correct Answered:
Wrong Answered:
A
Bandwidth minimized
B
FM less noise
C
Synchronization easier
D
None
FM sound less noise prone.
Correct Answered:
Wrong Answered:
A
2-1,3-2,1-3
B
3-1,2-2,1-3
C
2-3,1-2,3-1
D
2-2,3-3,1-1
AF=20Hz-20kHz, IF=10-108MHz, RF=3kHz-300GHz.
Correct Answered:
Wrong Answered:
A
1-1,2-2,3-3,4-4
B
1-4,2-1,3-2,4-3
C
1-3,2-1,3-4,4-2
D
1-2,2-3,3-4,4-1
Superhet=image freq, FM=threshold, PCM=quantization, Delta=granular.
Correct Answered:
Wrong Answered:
A
I & II only
B
III & IV only
C
II,III only
D
I,II,III,IV
All given properties true.
Correct Answered:
Wrong Answered:
A
Adjacent channel rejection
B
Improved tracking
C
Increase tuning range
D
Reject image frequency
RF amplifier helps reject image frequencies.
Correct Answered:
Wrong Answered:
A
18kV
B
12kV
C
18.75kV
D
22kV
Vmax=Vc(1+m)=15(1+0.8)=27kV. Closest 22kV.
Correct Answered:
Wrong Answered:
A
Ground wave
B
Space wave
C
Sky wave
D
LOS wave
Sky wave propagation uses ionosphere reflection.
Correct Answered:
Wrong Answered:
A
Varactor diode
B
Reactance modulator
C
Armstrong modulator
D
By-pass modulator
By-pass modulation is not a method.
Correct Answered:
Wrong Answered:
A
Mixer-RF-Limiter-IF-Discriminator-Audio
B
RF-Mixer-Limiter-Discriminator-IF-Audio
C
RF-Amplifier-Mixer-IF-Amplifier-Limiter-Discriminator-Audio Amplifier
D
Mixer-IF-Amplifier-Limiter-Audio-Discriminator
Standard FM superhet receiver sequence.
Correct Answered:
Wrong Answered:
A
Both statements true
B
Both individually true but II not explanation of I
C
I true, II false
D
I false, II true
Higher modulation index increases power in sidebands.
Correct Answered:
Wrong Answered:
A
28-56 MHz
B
88-108 MHz
C
58-88 MHz
D
108-128 MHz
FM radio operates in the frequency range 88-108 MHz.
Correct Answered:
Wrong Answered:
A
Allows specific range
B
Allows all
C
Blocks all
D
Amplifies all
Band pass filter selects a specific frequency range.
Correct Answered:
Wrong Answered:
A
Less sensitive to input variations
B
Smaller size compared to rectifiers
C
Has low input ripple
D
Source of radio interference
SMPS has high ripple compared to linear supplies.
Correct Answered:
Wrong Answered:
A
SSB-SC
B
DSB-SC
C
Both A & B
D
None
Double Sideband Suppressed Carrier (DSB-SC) has no carrier.
Correct Answered:
Wrong Answered:
A
Position of pulse is changed
B
Width of pulse varies
C
Height of pulse ? sampled value
D
None of the above
PAM uses pulse amplitude proportional to sample.
Correct Answered:
Wrong Answered:
A
Differentiator
B
Integrator
C
Demodulator
D
None of the above
FM to AM conversion requires differentiator.
Correct Answered:
Wrong Answered:
A
42.5 kHz & 37.5 kHz
B
45 kHz & 35 kHz
C
50 kHz & 30 kHz
D
25 kHz & 15 kHz
Sidebands=fc?fm=35?7.5=42.5 & 27.5. Closest option A.
Correct Answered:
Wrong Answered:
A
A Fraction of Transmission Bandwidth
B
The Entire Transmission Bandwidth
C
A Bandwidth equal to each input signal
D
None of the above
In TDM, each signal uses a fraction of bandwidth but different time slots.
Correct Answered:
Wrong Answered:
A
High pass filter
B
Band pass filter
C
Low pass filter
D
None of the above
Pulse Amplitude Modulated signals are recovered using a low-pass filter.
Correct Answered:
Wrong Answered:
A
Amplitude modulated and at the low-frequency end of each channel allocation
B
Frequency modulated and at the low-frequency end of each channel allocation
C
Amplitude modulated and at the high frequency end of each channel allocation
D
None of the above
Picture signal in TV is amplitude modulated at low-frequency end.
Correct Answered:
Wrong Answered:
A
Interlace Ratio
B
Max Horizontal Deflection
C
Aspect Ratio
D
Diagonal Ratio
4:3 is aspect ratio of TV screens.
Correct Answered:
Wrong Answered:
A
Class-C Amplifier
B
Class-B push-pull Amplifier
C
Class-A Amplifier
D
Class-D Amplifier
Class-C amplifier is used for modulation in transmitters.
Correct Answered:
Wrong Answered:
A
Conduction, valence
B
Valence, conduction
C
Valence, drift
D
None
Filled bands at 0K = valence; higher = conduction.
Correct Answered:
Wrong Answered:
34. Match List-I (Materials) with List-II (Type): i. Copper ii. Silicon iii. Silicon+P iv. Silicon+Al. Types: 1. Conductor 2. P-type 3. N-type 4. Intrinsic. Choose correct.
A
(i)-1, (ii)-4, (iii)-3, (iv)-2
B
(i)-2, (ii)-3, (iii)-1, (iv)-4
C
(i)-3, (ii)-2, (iii)-1, (iv)-4
D
(i)-4, (ii)-1, (iii)-2, (iv)-3
Copper = conductor; Silicon = intrinsic; P-doping = N-type; Al-doping = P-type.
Correct Answered:
Wrong Answered:
35. Hall effect principle applied in: 1. Magnetic field sensing 2. Current measurement 3. Hall effect sensors 4. Linear/angular displacement. Which are correct?
A
1,2
B
2,3
C
1,2,3
D
1,2,3,4
Hall effect is applied in all listed areas.
Correct Answered:
Wrong Answered: